#include <atcoder/modint>
#include <bits/stdc++.h>
using namespace std;
using namespace atcoder;
const int L = 0, R = 1;
using mint = modint1000000007;
mint solve(string &str, int bound, int src, int target) {
int n = str.length();
vector<vector<mint>> dp(bound + 5, vector<mint>(2, 0));
// dp[pos][ch] is the number of unique subsequences to reach pos when the
// last character is ch.
for (char ch : str) {
auto ndp = dp;
for (int pos = 0; pos <= bound; pos++) {
mint sum = dp[pos][L] + dp[pos][R];
if (ch == 'l' && pos) {
ndp[pos - 1][L] = sum;
}
if (ch == 'r') {
ndp[pos + 1][R] = sum;
}
}
if (ch == 'l' && src) {
ndp[src - 1][L] += 1;
}
if (ch == 'r') {
ndp[src + 1][R] += 1;
}
swap(dp, ndp);
}
// Empty sequence needs to be counted separately.
return (src == target) + dp[target][L] + dp[target][R];
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
string str;
cin >> str;
int bound;
cin >> bound;
int src, target;
cin >> src >> target;
cout << solve(str, bound, src, target).val() << "\n";
return 0;
}