Codeforces
CF Step
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Statement : A. A Simple Sequence

A. A Simple Sequence

You are given an integer $n$. You need to construct a permutation$^{\text{∗}}$ $a_1, a_2, \ldots, a_n$ using integers from $1$ to $n$ such that the following condition is satisfied:

$$$ a_1 \bmod a_2 \ge a_2 \bmod a_3 \geq \ldots \ge a_{n-1} \bmod a_{n}, $ where $u$ mod $v$ denotes the remainder of dividing $u$ by $v$.

If multiple valid permutations exist, you may output any of them.

It can be shown that a valid permutation always exists for every $n \ge 2$.

$^{\text{∗}}$A permutation of length $n$ is an array consisting of $n$ distinct integers from $1$ to $n$ in arbitrary order. For example, $[2,3,1,5,4]$ is a permutation, but $[1,2,2]$ is not a permutation ($2$ appears twice in the array), and $[1,3,4]$ is also not a permutation ($n=3$ but there is $4$$$ in the array).


Input

Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 100$). The description of the test cases follows.

The first line of each test case contains a single integer $n$ ($2 \le n \le 100$).


Output

For each test case, output on a single line $n$ space-separated integers $a_1, a_2, \ldots a_n$.

If multiple valid permutations exist, you may output any of them.


Example

Input

4
2
3
4
5

Output

2 1
2 3 1
2 4 3 1
3 5 4 2 1

Note

Note

In the second test case, $2 \bmod 3 \ge 3 \bmod 1$, so the permutation $[2, 3, 1]$ is valid.

In the third test case, $2 \bmod 4 \ge 4 \bmod 3 \ge 3 \bmod 1$, so the permutation $[2, 4, 3, 1]$ is valid.